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为您详解PHP开发工具的使用与分析

By: 盖茨 发表于 2008-11-7 11:29:42 · 3994次点击   回复:0   
有一段时间一直迷惑于PHP中引用的传递,后来查手册及C源程序,并反复测试,大致对引用传递在内存中的模式有了一定的了解,后来为了加深印象,写了个总结,应该不会有大的问题——当然这是在PHP4中,在以后的版本中可能会有变化。当时写总结的时候,想锻炼一下英语,因此就凑合了一篇。不过本人英语不好,也懒得翻译,反正当时想自己看得懂就行了。今天心血来潮,突然觉得还蛮有用的,于是在这里现丑了,请大家指正。那位看得懂的帮忙翻译一下吧,我没空了。

以下为引用的内容:
<?php  
/*  

filename: SetGetTest.php  

comment on assignment by value and referrence  
assuming $var is a varialbe, its handle(pointer) is named as *var,  
and its content is named as @var  

the memory area of @var is referred by *var, if the *var is the same,   
then the memory areas are the same, so *var is just like a pointer.  

1. when $var = $var1  
@var copied from @var1, but in the different memory area,   
new *var assigned by the system, pointing to the memory area holding @var  
*var and *var1 are different  

2. when $var =& $var1,  
*var assigned by *var1, and the @var is not assigned or copied,   
it is absolutely the same as @var1, and in the same memory area  
both *var and *var1 pointing to the memory area, that means they are the same.  

passing by referrence  
3.   
function set1(&$s){  
$var =& $s;  
}  
set1($var1) results:  
*var1 passing to the function, and *s is the same as *var1,  
then *var is the same as *s, the result is that *var is the same as *var1  
and all the contents are the same obviously.  

4.  
function set2(&$s){  
$var = $s;  
}  
set2($var1) results:  
*var1 passing to the function, and *s is the same as *var1,  
but when $var = $s executes, from 1. we can see @var is the same as @s,   
but *var is different from *s, so @var and @s is not in the same memory area,  
while @s and @var1 is sharing the same memory area, also *var1 and *s are the same.  

5.  
normal function return:  
function get(){ return $var1; }  
assuming the result is referred by a variable $result.  
then @result is copied from @var1 but *result is not the same as *var1  
when $var = get();  
first you get a variable $result, as I said above, @result is the same as @var1, but *result  
is different from *var1, and next $var = $result executes.   
As I said in 1., you can find, @var is the same as @result and the same as @var1,   
but *var is different from *result AND *var1;  

while $var =& get() just means:  
*var is the same as *result, so @var and @result are in the same memory area,   
but they are still different from those of $var1,   
both the memory area of @var1 and *var1,  




6.  
returning by referrence  
function &get(){ return $var1; }  
there are two ways to get the result  

$var = get(); and $var =& get(); now I will tell the difference  
I. $var = get();  
the *result is the same as *var1 and so @result and @var1 are the same.  
and then $var = $result executes,   
*var is not the same as *result, and also different from *var1,   
but their contents are the same.  

I. $var =& get();  
the *result is the same as *var1 and so @result and @var1 are the same.  
and then $var =& $result executes,   
this means $var and $result are the same, both of @ and *  

*/  

// the test is the following  

function println($s = ""){  
print "$s<br>\n";  
}  

class GetSetTest  
{  
var $var = null;  

function setByRef(&$arg){  
$this->var =& $arg;  
}  

function passByRef(&$arg){  
$this->var = $arg;  
}  

function setByVal($arg){  
$this->var = $arg;  
}  

function &getByRef(){  
return $this->var;  
}  

function getByVal(){  
return $this->var;  
}  
}  

$o = new GetSetTest;  

println("============ setByRef getByRef =============");  
println("-----------------Before change----------------");  
$in = "before change";  
$o->setByRef($in);  
$outByVal = $o->getByRef();  
$outByRef =& $o->getByRef();  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println("-----------------After change-----------------");  
$in = "after change";  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println();  

println("============ setByRef getByVal =============");  
println("-----------------Before change----------------");  
$in = "before change";  
$o->setByRef($in);  
$outByVal = $o->getByVal();  
$outByRef =& $o->getByVal();  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println("-----------------After change-----------------");  
$in = "after change";  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println();  

println("============ passByRef getByVal =============");  
println("-----------------Before change----------------");  
$in = "before change";  
$o->passByRef($in);  
$outByVal = $o->getByVal();  
$outByRef =& $o->getByVal();  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println("-----------------After change-----------------");  
$in = "after change";  
println("\$in: ".$in);  
println("\$outByVal: ".$outByVal);  
println("\$outByRef: ".$outByRef);  
println("\$this->var: ".$o->var);  
println();  

/*  
以下输出结果是我(夜猫子)擅自编辑添加的,主要是为后来人查看方便加在这里,越肉代庖,向longnetpro致歉  
输出结果:  
============ setByRef getByRef =============  
-----------------Before change----------------  
$in: before change  
$outByVal: before change  
$outByRef: before change  
$this->var: before change  
-----------------After change-----------------  
$in: after change  
$outByVal: before change  
$outByRef: after change  
$this->var: after change  

============ setByRef getByVal =============  
-----------------Before change----------------  
$in: before change  
$outByVal: before change  
$outByRef: before change  
$this->var: before change  
-----------------After change-----------------  
$in: after change  
$outByVal: before change  
$outByRef: before change  
$this->var: after change  

============ passByRef getByVal =============  
-----------------Before change----------------  
$in: before change  
$outByVal: before change  
$outByRef: before change  
$this->var: before change  
-----------------After change-----------------  
$in: after change  
$outByVal: before change  
$outByRef: before change  
$this->var: after change  
*/  

?>
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